Hi all this may be a bit of a long post or I may break it into sections I don't know yet. In a previous post I showed how simple it was to layout the inner three planets using a simple 9 by 11 triangle and the height and base of The Great Pyramid but now we are going to expand on this and go to another level of sophistication. What follows was discovered by a gentleman named Nick L. as he and I searched for answer on The Giza Plateau but what follows is his and it is beyond remarkable and sadly it has gone sorely underestimated and under appreciated but I will post it here for you to enjoy. As I said it is amazing.
To begin we will start with the discovery of mine that the ratio between The Great Pyramid and G2 or the one commonly referred to as Khafre's Pyramid is in the exact proportion of the square root of 3 to the value Phi or The Golden Ratio. In mathematics and the arts, two quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities, i.e. their maximum. The figure below illustrates the geometric relationship.
So this translates to:
a = 1.00000
b = .618033988
a + b = 1.618033988
And Phi is equal to 1.618033989 while Phi squared = 2.618033989 and 1 divided by Phi = 0.618033989 and lastly 1 divided by 0.618033989 = 1.618033989
So according to me The Great Pyramid or 440 cubits is equal to the square root of 3 or 1.7320508075688772935274463415059 while G2 or Khafre's Pyramid is equal to 411.04 cubits and Phi or 1.6180339887498948482045868343656. So let's do some division and see if I am correct in my discovery.
G1 / G2 = ?
440 / 411.04 = 1.0704554301284546516154145581938
But we have decided that G1 / G2 is equal to or is the same as √3 / Phi
√3 / Phi =
1.7320508075688772935274463415059 / 1.6180339887498948482045868343656 = 1.0704662693192697958259095291383
The degree of accuracy is 1.0704554301284546516154145581938 / 1.0704662693192697958259095291383 = 0.99998987 almost a perfect match. Close enough however to conclude this is indeed what was meant.
Okay now for a very quick recap. Here is the triangle when we last saw it.
What Nick did next was the stuff of genius. He decided that to solve for our solar system he needed to use all three pyramids at Giza and this he did in a most amazing and profound way. For by using all three pyramids he solved not only the correct placing of Venus (where I had only been approximate) but manged to also place Mars correct to a degree of accuracy that again goes far beyond the realms of coincidence.
Fist of all let me list the three sizes for the three pyramids at Giza.
First and largest is The Great Pyramid and the base of it is 440 cubits
Second is G2 or Khafre's Pyramid and it is 411.04 cubits
and third is Menkare's pyramid and it is 201.46 cubits.
We have used The Great Pyramid's height and base to find Mercury and Earth and an approximation for Venus but Nick took it up a notch when he devised this simply but profound drawing by using G2 in a most remarkable and simple way. Observe:
Nick then found something even I was mesmerized by, by the sheer genius of it. He managed to find Mars as well and to do this he brought in the smallest of Giza Pyramids and used it in a way only someone on a roll would think of doing. It is remarkable again in it's simplicity and for the fact that he found it. But first a bit about G3 and the smallest of the pyramids. Firstly and foremost is the fact that the first quarter of it from the ground up was encased in RED GRANITE. Was this perhaps a bit of a hint that G3 was meant to show us Mars, the red planet ? Also interestingly the west face of G2 or the middle pyramid is precisely 353.5534 cubits from the west face of G3 and 353.5535 is precisely 1000 times the square root of 2 DIVIDED BY FOUR !!! or 1/4 or the square root of 2 !!!
And now let's continue with the genius of Nick L.
As I mentioned the base of G3 or Menkare's Pyramid is 201.46 cubit's and working with that nothing was able to be found but then Nick did something quite clever he decided to calculated THE DIAGONAL OF G3 and this we find is √201.46² x 2 or √40586.1316 x 2 or √81172.2632 or 284.91. Nick then had the idea to subtract 284.91 from the bottom base of our triangle and got 880 (2 x 400) - 284.91 or 595.09 cubits. Nick then decided to add this to our hypotenuse which we had calculated to equal 1137.01363 cubits or √9² + 11² = √202 or 14.212670403551895496970929487628 and by the way 1137.01363 cubits = 440 x 2.584122 Here is the final drawing for the four inner planets of our solar system.