Friday, August 14, 2015
Sunday, August 2, 2015
And an old image revisited.
Continuing our story ... The Measurements at Giza: Part III
Hi all. Please see my latest website on The Measurements of The Universe: Part IV More Proof of Divine Planning ? A Second Solar System Examined: Click the following link:
From Whence Comes The Measurements: Part IV
Hi all ...
I have continued my study of our solar system looking for an easy way to plot Mars using the diameters of Mercury and Mars itself and came up with this. It is I think ... well you have a look and tell me.
ASSUMPTION # 1 ... The distance from The Sun to Jupiter is by default 10,000 times the square root of 2 or 10,000 times 1.41421356 or 14142.1356 CUBITS !!!!!
WHAT FOLLOWS ... Using this as a given we can see in the diagram that the distance from Mars to Jupiter is equal to precisely 10,000 cubits and the distance from The Sun to Mars is 4142.1356 cubits
Following that we can see that the distance from The Sun to Mercury is 1052.33 cubits or 201.46 (P3) + 411.04 (P2) + 439.83 (Perfect Pi base for G1)
I then scaled and placed The Giza Rectangle on the diagram in order to plot Venus. (One circle is 9/11ths of the distance to Mars and the second is what is left from the diagonal of the approximate 9 by 11 rectangle)
It is a pretty simple way to plot the first 6 planets and it is an easy one to remember as well.
I have mentioned this before but I think this diagram makes it hit home a little clearer and a little more exciting.
May I present "The Great Pyramid Solar System"
Please note here that using Mars as the origin point and 9 units as a radius we define the place of Ceres. And if we use the opposite point west of Mars at 9 units and scribe an arc to intersect our hypotenuse we have defined the distance to Venus. All in all a very neat, simple way of looking at our solar system and is it any wonder that The Ancients would have known this. Here is a very neat diagram but there is still more.
Mars two face
And here is the final image. Note how the Great Pyramid and our solar system lends itself to such a simplistic diagram layover. It is very neat.
Tuesday, July 14, 2015
From Whence Comes The Measurements
Part II "From The Solar System to Giza"
First Up: Mercury " Messenger of The Gods"
The Messages Revealed
Hi all I hope you enjoyed Part I and if you have not read it may I suggest to get a nice background to this page it would be advantageous to do so. First off let me post the final image from that page again here to see where we left off.
As you can see we very nicely, using the measurements of our solar system and the distances between the four inner planets, discovered that they did indeed give us the correct ratios of the measurement systems we are so familiar with, The Royal Cubit. The Meter and The Megalithic Yard to a degree of accuracy of 99.98 %. But there is still so much more to see. From another of my websites you might remember that I showed how the diameters of all the planets, I excluded Pluto, added up to 10 times Pi or 31.41592659. Here is my diagram for that.
Well there is one more measurement we have to
add to the top image and that is this fascinating fact. Not only
do all the planets total 31.41592659 Earth diameters but if we
use this 10 times Pi as inches so that is 31.41592659 inches and
allow it to equal a certain solar distance then another agreed
upon and well known distance equals the correct number of inches
in the ancient Royal Cubit. Allow me to demonstrate. We are going
to use the semi major axis of Earth and Mars, that is 149,598,261
kilometers and 227,939,100 kilometers. But let's do the simple
31.41592659 / 20.62 (inches in a Royal Cubit) = 1.523565787386. So if I am correct then 227,939,100 / 149,598,261 should equal the same or very close. The calculator please ...
227,939,100 / 149,598,261 = 1.523674797263 - The accuracy of this is 1.523565787386 / 1.523674797263 = 0.99993 to degree of accuracy of 99.993 %
I think it is safe to conclude that the ratio of the semi-major axis' of Earth and Mars equals the ratio 10 x Pi to The Royal Cubit.
Let's add this to our slowly getting cluttered diagram.
All this is very neat, tidy and accurate.
Mercury " Messenger of The Gods"
Okay we are now going to look at the planets individually and see if they got involved in the measurement systems we use as well. We will start with Mercury. It is the swiftest planet, circling The Sun in 87.969 days and also the smallest (excluding Pluto) with a diameter of 4879.4 kilometers. In Roman mythology he was the messenger of Jupiter, and wore a winged cap and winged shoes. He bore in his hand a rod, or magic wand, entwined with two serpents, called the Caduceus. Here is what another website says about Mercury:
Mercury is the smallest and innermost planet in the Solar System. But heres a question, how did Mercury get its name?
Like all the planets, Mercury is named after one of the Roman gods, which were based on the gods worshiped by the Ancient Greeks. The Roman god Mercury was the son of Maia Maiestas and Jupiter in Roman mythology, and most of his aspects were based on the Greek god Hermes.
According to mythology, Mercury was the swiftest of the gods, and the one that merchants prayed to for success in their commercial transactions. And Hermes was known as the messenger of the gods in Greek mythology. This is appropriate since Mercury is the innermost planet in the Solar System, and appears to move quickly from night to night.
Since Mercury was visible with the unaided eye, most of the ancient cultures had their own name for Mercury. The ancient Babylonians called the planet Napu, after a god in their mythology. The ancient Greeks actually thought that Mercury was two planets, and they called it Apollo when it was visible in the morning sky, and Hermes when it was seen after sunset. But in the 4th century BCE, ancient astronomers realized that the two objects were one and the same, and stuck with Hermes; becoming Mercury with the Romans.
And about Hermes we have this:
Hermes is a god of transitions and boundaries. He is quick and cunning, and moves freely between the worlds of the mortal and divine, as emissary and messenger of the gods, intercessor between mortals and the divine, and conductor of souls into the afterlife. He is protector and patron of travelers, herdsmen, thieves, orators and wit, literature and poets, athletics and sports, invention and trade. In some myths he is a trickster, and outwits other gods for his own satisfaction or the sake of humankind. His attributes and symbols include the herma, the rooster and the tortoise, purse or pouch, winged sandals, winged cap, and his main symbol is the herald's staff, the Greek kerykeion or Latin caduceus which consisted of two snakes wrapped around a winged staff.
In the Roman adaptation of the Greek pantheon (see interpretatio romana), Hermes is identified with the Roman god Mercury, who, though inherited from the Etruscans, developed many similar characteristics, such as being the patron of commerce.
But I believe a slightly different meaning for Hermes and the later Mercury. I believe that Hermes came from Egypt and is a Greek form of Thoth and this is what is said of Thoth:
""Thoth was called in the Pyramid Texts'
He who reckons the heavens, the counter of the stars and the
measurer of the Earth', the inventor of arts and sciences, scribe
of the gods, the 'One who made calculations concerning the
heavens, the stars and the Earth'. As the 'Reckoner of times and
of seasons', he was depicted with a symbol combining the Sun's
disk and the Moon's crescent upon his head, and - in words
reminiscent of the biblical adoration of the Celestial Lord - the
Egyptian inscriptions and legends said of Thoth that his
knowledge and powers of calculating 'measured out the heavens and
planned the Earth'. His hieroglyphic name Tehuti is usually
explained as meaning 'He who balances'. Heinrich Brugsch
(Religion und Mythologie) and E. A. Wallis Budge (The Gods of the
Egyptians) interpreted that to mean that Thoth was the 'god of
the equilibrium' and considered depictions of him as 'Master of
the Balance' to indicate that he was associated with the
equinoxes - the time when the day and the night were
- Jean-Philipe Lauer, Saqqara
But I digress a bit so back on track. I have found that Mercury that closest planet to The Sun should have been called Thoth because it has placed where it is to measure the solar system for us. And it is a messenger of The Gods but in this case The Gods are the planets and Mercury, Hermes, Thoth are giving us the measurements of The Gods and that is the message they are delivering. Farfetched ? Not so and I have a boatload of facts to back up my hypothesis. But for the moment back to measurements.
The diameter of the four inner planets are as found below:
|Planet||Diameter in kilometers|
For now we will just concentrate on Mercury and Mars. Can they show us the ratio of any meassurement systems we use. What do you think ? Do you think I can show you that they do indeed show us and to a degree of accuracy you will find hard to believe. However it is where I found this little trick that is so profound. I found it where I found most of my discoveries and that was on the barren plateau in Egypt called ... The Giza Plateau and those three incredibly encoded structures referred to as The Pyramids of Giza.
The ratio: The Royal Cubit to The Foot = 20.62 inches to 12 inches = 1.7183333333
The Planetary Solution: ..... Incredibly simple. Mars + Mercury / Mars = 4879.4 + 6792.4 / 6792.4 = 11671.8 / 6792.4 = 1.71836 = 0.99998 = 99.998 % So if we add Mars and Mercury together and divide by Mars we get the precise ratio of a Royal Cubit to The Foot
Now I don't know if you are amazed by this but you should be. I will now show you how it was first discovered by Nick Lievense a genius, but I don't think he knows it yet.
Now I have contended for quite some time that not only is The Great Pyramid representing The Earth but it is also representing Mercury and here is the first of the proofs I will offer.
The ratio: Mars + Mercury / Mars = 4879.4 + 6792.4 / 6792.4 = 11671.8 / 6792.4 = 1.71836 can be written (a + b) / b = 1.7183 with a = Mercury and b = Mars
Now there are probably millions or maybe countless numbers that will satisfy this equation but only one series that I have found at Giza and they are so in your face you will find it hard to believe you missed it before. Okay so now it's time to introduce those giants of construcution wonders, The Pyramids at Giza.
The three pyramids at Giza have base lengths of 440 cubits (average about 9069.4 inches and The Great Pyramid), 411.04 cubits (about 8471 inches and G2) and 201.46 cubits (4153.6 inches and G3)
Here is a layout of where they are located within the Giza Plateau: NOTE ! This image copyright to the estate of Clive Ross
And another this one a gift to me:
And with the measurements marked.
I didn't see it right away but then it all became very clear. If we add 411.04 (G2) + 201.46 (G3) (Total 612.50) and divide by 440 (G1) we get 612.50 / 440.00 = 1.392045455 now that was virtually the same number as when we divided Mars diameter of 6792.4 by Mercury's diameter of 4879.4 as 6792.4 / 4879.4 = 1.392056400. This checks to an unbelievable 0.999992 or 99.9992 % or 8/10,000 ths of 1 percent. I think they would give you ar least 10 billion to one odds in Vegas that three randomly built pyramids would check to Mercury and Mars diameters to that accuracy. But of course that is not all it encodes for we can not forget about this ratio: The ratio: The Royal Cubit to The Foot = 20.62 inches to 12 inches = 1.7183333333 - So we have this final little gem. G1 + G2 + G3 (1052.50) / 612.50 (G2 + G3) = 1.7183 - But wait this is also equal to Mars + Mercury / Mars so therefore Mars must equal G2 + G3 and of course Mercury has to equal G1 or 440 ... And that as they say is just the very tip of a very big and very deep iceberg. Below are the closing images I would like you to leave with:
and this last one for now.
This is the beginning of the proof I will offer that The Great Pyrmaid is indeed meant to represent Mercury. After this opening I hope that what follows will be a little easier to accept.
I hope you approve Nick !
Cheers and much more to follow.
Best Don Barone
July 13th, 2015
Saturday, July 11, 2015
From Whence Comes The Measurement ?
Hi all especially Nick L., Charlotte and a poor soul named Carol Behan from over at Graham Hancock's Message Board who had this to say about me and my work knowing full well I have been barred from there and thus prevented me from responding so I will do it here ... anyway this is what she posted ...
Carol Behan: If you play around with numbers for any length of time, you can get any correlation you want. That doesn't mean you've proved anything, though. This is exactly what Ahatmose was doing for years on end in his posts - wasting years of his life on trying to piece together futile correlations.
And I say this ....
How dare I. How dare I try to find an answer on the other side of the box which most of humanity has been locked in. How dare I try to find answers in all the most illogical places. Imagine looking for answers within one of The Creator's most eloquent creations ... The Solar System ! But you know what not once did I take credit for any of my discoveries. I never once said it was my own. No every single time I gave credit where credit was do and that belonged solely with those incredible entities (human or otherwise) who built The Giza Pyramids and already had it all encoded. I simply found a key to unlocking part of it. My numbers fit almost to perfection. Not 94 or 95 or 96 % but almost always to at least 99.98 % accuracy or better, yet still my work is ignored or I really should say their (The Ancient Builders) work is ignored. I honestly have to laugh when my detractors choose to try to tell me that the measures came from the thumb and the foot and the span and the digit and yet are so blind to expand their thoughts just a little and try to take into consideration that yes although these simple tools do work the Creators who "created" man to certain specifications, I believe in "His" image it is said, had first built The Heavens and our Solar System. I would like to ask a simple question here. If "The Creator" used "himself" as a guideline for Mankind does it not seem perfectly logical that "he" would have used the same blueprint to define the heavens and most certainly The Solar System and with that thought in mind let us move forward. But be forewarned this may be a waste of your time and your life and you obviously have so much more and better things to be doing.
Nick L. was a person who arrived out of nowhere over at Graham Hancock's Message Board and for some insane reason took to my postings with a passion. He took my short little pass of an idea and turned it into the greatest of touchdowns and what he discovered or really rediscovered or maybe even co-discovered with me (it gets murky here and is really not important) is astounding and if a big name author had come to these conclusions it would have been everywhere for people to see and talk about. But alas it fell to a Grade 12 dropout to figure it out and take an early pass from the greatest thinker at Giza ever to be seen or likely ever to be seen again, The Late Clive Ross, and with Nick L. help turned it into a truly noteworthy discovery. But it continues to be ignored and this is fine I guess but it is simple and amazingly accurate. It is there to be checked and it is simply ... The Truth.
I have done an awful lot of research at Giza and I dare say few (DUNE being a notable exception) know the measurements of The Giza Plateau as well as or better than I do. But what makes my research so different ? It is simply that I feel that all of the measurements of humanity were first manifested and derived within and from The Solar System and gives a clear and concise meaning to As Above ... So Below. Also I would be remiss if I didn't mention The late Alan Bennett and his website Solar Geometry: A Case for Divine Design of the Solar System which was also a wonderful encouragement for me. Did he waste his life as well Carol ?
Before we move on there are a few facts that need to be agreed upon and are in the scientific community and these are the semi-major axis of the planets. The semi-major axis is simply the average distance a planet is from The Sun and is arrived at by taking it's closest approach to The Sun added to it's furthest distance away from The Sun and simply then dividing the result by two. As an example let us use Mercury. It's closest approach to The Sun is 46,001,200 kilometers and it's furthest point away from The Sun in it's orbit around The Sun (all orbits being elliptical) is 69,816,900 kilometers with the average of the two being 57,909,050 kilometers. Let us put them in a chart format. For this posting I am only going to be dealing with the four inner planets, Mercury, Venus, Earth and Mars. It is my contention that within the measurements of these four planets can be found the relationships between The Foot, The Meter, The Cubit and best of all The Megalithic Yard. So on to the planets. To see the source of my figures click on the links in light grey.
|Planet||Semi-Major Axis (in kilometers)||Ratio with Mercury 1||Distance to next closest planet|
|Mercury||57,909,050||1||50,298,950 (Mercury to Venus)|
|Venus||108,208,000||1.8685853075||41,390,261 (Venus to Earth)|
|Earth||149,598,261||2.5833312928||78,340,839 (Earth to Mars)|
Here are a series of images to show you the values.
Okay so these distances are as accurate as can reasonably get these days and the ratios I have taken to nine places simply because the numbers we are dealing with all have at least nine significant figures as well and it is important to maintain accuracy.Okay let's do some more ratio checks. Now remember a ratio is simply the number one distance will go into another. so for example Venus is 108,208,930 kilometers from The Sun and Mercury's distance is 57,909,050 kilometers so Mercury's distance from The Sun will divide into Venus' distance from The Sun a total of 1.8658.... times and so on. So let's try a few more. From the chart above here is 78,340,839 which is the distance from The Earth to Mars. Earth is 149,598,261 kilometers from The Sun. So the distance from Earth to Mars divides into Earth's distance from The Sun a total of 149,598,261 / 78,340,839 or a ratio of 1:1.90958206358. Remember that number as it will prove to be of major importance. Okay let's do one more before we move on to a more human based measuring system. The distance from Venus to Earth (from the chart above) is 41,390,261 kilometers and the distance from The Sun to Mercury is 57,909,050 kilometers. So the distance from Venus to Earth divides into the distance from the Sun to Mercury ( 57,909,050 / 41,390,261) a total of 1.39909844975 ... near enough I should think to call it an even 1.4
Okay now we have to figure out the ratios of the major
measurement systems that are used today and have been used in the
past. Let's list them. The Foot, The Cubit, The Meter and one
that not too many agree is even a measurement, The Megalithic
Yard. In order to compare them we need a smaller agreed upon
distance that can be divided into each of them and for that we
can use the lowly inch however it could be anything smaller as it all is simply a ratio. Below is a chart to show how many inches
are in each unit of measurements. Observe. No tricks. No
gimmicks, nothing that can be argued with. These are the cold
hard facts concerning the measurement we use to day. I am going
to highlight a couple of them because we will be returning to
|Unit of measurement||Number of inches in each unit||Ratio of Foot to The others||Ratio of Cubits to the others|
|The Cubit||20.62 (agreed upon but some debate)||1.718333333||1|
|The Megalithic yard||32.64838856||2.720699046||1.5833360116|
So now let's combine what I have written above with what is in the chart and lo and behold we get this diagram.
And we can see that the ratio of a meter to a cubit (39.37 inches / 20.62 inches) = 149,598,261 km (distance from The Sun to Earth) / 78,340,839 (distance from Earth to Mars)
For those who would like to know how close these ratios are to each other here are the calculations:
39.37 / 20.62 = 1.9093151668
149,598,261 km / 74,340,839 = 1.9095820636
They check for an accuracy of 1.9093151668 / 1.9095820636 = 0.99986 or 99.986 % accurate.
But more exciting ratios await the discerning student. Let's take a look at how many times the distance from The Sun to Mercury divides into the distance from The Sun to Earth. As already calculated in the chart above it is 2.5833312928 but the keen observer would notice that the ratio of a Cubit to a Megalithic Yard was 1.5833360116 But wait if we subtract 1 unit (or actually simply the distance of Mercury from The Sun) out of the overall distance from The Sun to Earth we are left with 1.5833312928. This distance ratio represents how many times Mercury's distance will divide into the distance from Mercury to Earth AFTER ITSELF HAS BEEN DEDUCTED.. So now unbelievably we find The Megalithic Yard within the cosmos as well for if we assign the distance from Mercury to The Sun as 1 cubit then the distance from Mercury to Earth is equal to a value almost exactly equal to The Megalithic Yard. Again for those who would seek to see how accurate our Solar System is here are the calculations. 1.5833312928 / 1.5833360116 = 0.999997 which translates to a degree of accuracy of 99.9997 %
The megalithic yard I have chosen to use is 1/4 of the circumference of a circle with radius of the square root of 3. This calculates to: = 1.7320508076 x 2 x Pi all divided by 4 = 10.88279618541 / 4 = 2.72069904635 More to come shortly
Thursday, November 6, 2014
Well here we are at Dahshur and for those who have lived in a bubble and do not know what The Bent Pyramid looks like here is a picture of it.
As you can see there appears to be two pyramids and here is the sketch we will be using.
John Legon did a lot of great work on these things in the mid 80's but his main fault I feel is that he insisted that The Giza Plateau was in the ratio of the square root of 2 to the square root of 3 rather than trying a more simple and accurate 9 by 11 rectangle. It is because of this fact that most of his work at Giza is in error and does not fit. If we allow 20.62 inches to a cubit then The Giza Rectangle works out to be 1417.5 cubits wide or 29228.85 inches by 1732.50 cubits or 35724.15 inches. These are the facts and the distances as presented by Petrie and I am not sure why John would have insisted that they were not correct. Maybe I will ask him. Anyway after experimenting with 110 for the top and 90 cubits for the bottom pyramid height I finally decided to take the advice of John Legon and use 110.1 cuibts for the upper height. Here are the break downs according to Petrie and Dorner. Again borrowing from Johm Legon's website. Let us look first at the break downs for the two heights.
But before we do any of this we have to decide on the angle of the upper portion and so I am going to go with The Master Builders and use the angle they left us at Giza of 43.3637 and the tan ratio of 0.94445 . So to start with let us assume that they copied (oh wait they were first) , that they used for a top height the distance of 110.1 cubit what would that give us. Well it reall is a simple matter. one only has to take 110.1 and divide it by 0.94445 to get 1/2 the base of the upper portion and thsi gives us 110.1 / 0.94445 and equaling 116.576 and tiems 1 we have a base of 233.152 cuibts for the upper base. Here is a diagram to illustrate this.
And finally showing the contained angle.
Just a note here that we match Dorner measurement of 110.11 within 1/100th of a cubit. Keep that in mind as we solve for the bottom angle and distance. of base.
The next stage was to figure out what the base dimension was. Was it 360 cubits as some ahd proposed or was John legon correct with his guess of 362 based on explantions which are available on his website. I felt that the answer like all the answers I was now finding had it's roots at Giza and so began to experiment with various base. First I took 360 / 2 = 180 - 116.576 = 63.424 and divided into 89.9 (as per Johm Legon's plan of Giza) I got 1.41744 and an angle of 54.797 and with a base of 180.75 or 1/2 361.50 I got 64.924 / 89.9 = 1.3847 Neither of these reaslly di anything for me and then I decided to sqaure the base add on or 64.924 and got 4215.13 and that gave me an idea. What if we went back to G3 again and took the square root of the base this time and so I did this and got square root of 4153.6 or 64.4484. Now earlier I had multiplied 944.45 by 1.4 and got 1322.23 but this time I decided to use what we had at Giza and instead of multiplying by 1.4 I decided to multiply by 1.39361 (13,936.1 inches north south between G1 and G2) and got this number 64.448 x 1.39361 equals 89.815 and virtually identical with what Dorner had for the lower height AND what he had for the total height of 199.92 as we get 199.916. So by using the measurements at Giza we have arrived at a probable correct solution for The Bent Pyramid. the only remaining thing we need to do is justify the total base of 116.576 + 64.448 or 181.024 and times 2 we get 362.048. But this is such an odd number. Why not 360 or 362 even why on Earth 362.048 ? Well ... But first a word on the ehight that we arrived at. We got 104.71 meters or 199.92 cubits probably doesn't mean too much to most but an interesting "co-incidence" has the ratio of the mass of Jupiter or Ju P(i)tah [Jupiter = Ptah] equalling:
One solar mass M☉ = 1,047.56 Jupiter mass (MJ)
and woudn't you just know it that 1,047.56 meters = (this is a punch line so get ready) 1,047.56 meters = 2000.12 cubits and just to keep this rolling since some would have The Red Pyramid with a base of 420 cubits ... well wouldn't you just know it that 440 cubits / 1.047.56 = 420.02 cubits so we are muddying the waters again but this time we have Jupiter involved instead of The Sun. But jsut found another one ... 1047.56 x 12 inches_ = I think this might be another punch line ... 104.756 cubits = 2160.07 inches and diameter of Moon in miles exact would have it:
... to be continued
Okay it is Thursday morning Nov. 6th and onward we go. Now what led to this latest round of insights was the fact that I chanced upon a diagram I had made around a year ago and although I thought it unique I did not pursue it. Here is the diagram from around September of 2013.
Now some might wonder how I figured out the angles on the diagram above but it is really quite simple geometry and trigonometry. In any right angled triangle the small side divided into the large side (not the diagonal) will yield a ratio or a number and this is called the "tan" of the angle in question so dividing 13162 by 13936.1 will give us the tan of the angle and the ratio turns out to be 0.9444536 and this is precisely what the distance is from the center of G2 to G3 along the horizontal multiplied by 10,000 ! Now I mean really think about that for a moment. Of all the measurements that randomly could have resulted from placing G3 on the plateau what do you think the odds are of placing it precisely 10,000 times the ratio of the distances between G1 and G2. Now we have met 10,000 here at Giza before when we realize that The Great Pyramid is representing the square root of 3 and the height of this pyramid in inches is precisely, or was projected to be, the square root of 3 divided by 3 times 10,000 and we get 5773.50 inches. But after coming to terms with this latest coincidence one then would need to try to explain the following. What follows was pointed out by me last year but it is within a better framework that I offer it this year.
There have been many arguements on whether The Ancient Builders knew Pi and/or decimals and all I can say is how the heck could they have left the distance between G2 and G3 the exact DECIMAL VALUE or ratio of the distances between G1 and G2 if they did not know decimals ? I mean really how long can "they" keep yelling ... COINCIDENCE !
There are 4 different measurements at The Great Pyramid for the sides and as I have suggested in the past this is becasue I feel that there is probably at least 4 different solutions But let's deal with just one scenario. Let us assume that The Pi angle was meant and used here at The Great Pyramid how would you prove to vistors to your pyramids that you had used Pi espeiclaly when 5.5 by 7 and Phi were so close. So how would you do it ? Well I am going to show how The Master Buidlers showed us !
In earlier posts I showed my reasoning for calling The Great Pyramid the square root of 3 and it is from that base that we branch out. The Pi angle is the ratio of Pi divided by 4 and so if the angle intended at Giza for G1 was indeed The Pi angle then 1/2 the base would be [(Pi / 4 ) times 5773.50] inches and we get 0.7853981634 times 5773.5026919 and we get 4534.4984 inches and multiplied by 2 gives us 9068.9968 or rounded off to 9069 inches well with the distances allowed at Giza which are as follows:
So we will stick with 9069 inches which is within one half of one inch to what is measured by Petrie. Now we can not forget about G3 which was miraculously placed precisely at the tan of the angle between centers of G1 and G2 but what of it's size ? Well here is what Petrie has for G3 ...
South = 4157.8 inches
West = 4153.9 inches
So let us start with the mean and round up to 4154 inches. If we add this to G1 we get G3 + G1 = 4154. + 9069.0 = 13223 inches and would it not be somewhat convincing if this number in some way showed us Pi given the numbers we have already been using well how about this. 4154 / Pi = 1322.26 this checks to 4/10ths of one single inch and has convinced me that they intentionally encoded their understanding of this ratio. But as always at Giza there is always one more proof and so I offer this. One of the sacred measuremtns used at Sakkara for their arches or curves was the ratio 0.7 or 1.4 ratio and so what do we get when we use 4154 and 1.4 with a little help from our friend Pi ... do I really need to do the math ... well it is none other than [(4154 / Pi) / 1.4 = 944.47 and again showing us our angle tan decimal of 9445. So what we have is G1 + G3 equal to 1/Pi x 10 or 3.183098862. If we allow this then G3 is equal to precisely 1 unit and G1 is equal to [(1/Pi x 10) - 1] or 2.183098862 and that is indeed what the numbers work out to. Are these just more coincidences ? I think not. In order to be a perfect fit we would only need 2/10th of an inch or 9069 / 2.183098862 or 4154.19. Proof I would suspect of intent. But we are not nearly done yet. Here is a diagram that illustrate this concept a bit better using 9068.8 and 4154.
But wait this post is supposed to be about The Bent Pyramid at Dahshur so maybe we should head on over there. see you there in a while ... to be continued.
Friday, October 10, 2014
In Part I it was shown by me how the AVERAGE speed of Neptune around The Sun was in the ratio of "the cube root of 1/2 the diagonal of The Great Pyramid (622.00 / 2) divided by 100 or 3.11 when we use the perfect measurements to show Pi of 439.82 for the base and 280.00 for the height . So I had a thought maybe ALL the planets were at a cube root of a number that we would find significance with and so I tried another planet and so I tried the one furthest from The Sun and that would be Pluto at about 5.874,000,000 kilometers from The Sun on it's semi major axis. I wondered could this give me a number that was important so I started trying "things" and came up with this marvelous solution. In books and online the suggested average speed of Pluto is anywhere from 4.67 to 4.7 ( I would guess that the latter was rounded) and that would give Pluto a ratio of Earth's speed of 29.78 / 4.67 or 6.37687366167 to 1. So in keeping with our theme I decided to cube this value to see what I would get and arrived at this number: 6.37687366167 cubed is 259.31249186591 but I have learned not to trust measurements online and so going to my elliptical measuring site I found out that the actual distance traveled by Pluto in a year is 36,348,870,300 kilometers. Now to calculate average speed we simply need to know how long a year is and we find two values for the year on Pluto. The first is "the sidereal orbital period" and this is 90,465 days while the second is "the tropical orbital period" and this is 90,588 days/ so now all we do is divide 36,348,870,300 kilometers by 90,588 / 24 (hours) / 60 (minutes) / 60 (seconds) and we get 4.6441528388 if we use 90,465 we get 4.65046722336. If we use the latter we get 29.78 / 4.65046722336 or 6.4036576476490935125430844545394 and this number cubed is 262.59371 (very close to the height of The Great Pyramid now and many feel that this is as high as it got) but the real numbers I am looking at are 6.3972269796157684960801651350896 and 4.6551420005717308801570872085312 for 29.78 / 6.3972269796157684960801651350896 = 4.6551420005717308801570872085312 okay be why 6.3972269796157684960801651350896 well this number cubed is Phi squared x 100 or 261.803398875.
Using these values we get 4.6551420005717308801570872085312 x 90,465 x 24 x 60 x 60 = 36,385,409,181.5 and the accepted value of 36,348,870,300 divided by 36,385,409,181.5 = 0.998996
So is the ratio of Pluto's average orbital speed to that of Earth's in the ratio of 1 to the cube root of Phi squared x 100 ?
Well what do you think ?
I was about to close this posting when I decided to see what the actual radius would be with our values for Pluto and got these values. For 36,348,870,300 if this was a perfect circle the radius would be 5,785,102,384 and if we used the number we got when we used Phi squared x 100 cubed then cube rooted we get 36,385,409,181.5 as the perfect circle and radius would be ... 5,790,917,728 and if we divide by 100 we get 57,909,177.28 and we have to be amazed that it is almost precisely the semi major axis of Mercury of 57,909,050 or an accuracy rating this time of 0.9999978 or about 1 in 22/10 millionths ! (22/10,000,000). So in other words we now have this solution for the orbital distance of Pluto. Actually quite easy to remember and quite brilliant as well. We simply use the semi major axis distance of Mercury (and how many times have I tried to tell you that Mercury is the messenger of the information of the gods ?) as a radius and simply calculate for circumference and we get 57,909,050 x 2 x Pi x 100 to get 36,385,329,211 and Phi squared x 100 cube rooted yields 36,385,409,182 simply amazing ... don't you think ?
But there is still a bit more and I will continue with a solution for Eris and an explanation (maybe) for the outer reaches of our solar system and The Oort Cloud in Part III of Cubes and roots and squares, oh my !